Problem 3
A triangle
has two of its vertices at
and
in a Cartesian coordinate system. Its third vertex is on the
axis. If the area of
the triangle is 2 square units, what are the possible coordinates for this
third vertex?
[Problem submitted by Juergen Pahl, LACC Professor of
Mathematics.]
Solution for Problem 3:

Equation of
Line 1: ![]()
Equation of
Line 2: ![]()
Point of
intersection: ![]()
and
then ![]()
Equation 1
Area of the
triangle ![]()
=
Equation 2
Substitute
Equation 2 into Equation 1:
![]()
Solve this
equation:
or
We get the
two possible solutions:
or ![]()
![]()